rencia lourens radmaste centre using the casio fx-82za plus for functions in the fet band
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Rencia LourensRADMASTE Centre
Using the CASIO fx-82ZA PLUS for functions in the FET band
Some remarksA calculator is a tool.Learners should
Know where answers come from.Understand mathematics.
Teachers shouldTeach the mathematics.Explain the reasoning behind why the
calculator methods work.BUT the calculator can (and should)
become a tool to assist.
CAPSFunctions form 35% of the Grade 12 paper
1, 45% in Grade 11 and 30% in Grade 10 (CAPS). The calculator can be used to support the calculations needed to draw and interpret the graphs of the functions.
Intersection of two graphsFind the points of intersection of the
straight line f(x) = x – 3 and the parabola g(x) = x2 – x – 6 if .
We need to beBe in TABLE mode.Have the DUAL table SETUP.
Who is NOT sure?
So how can I as a teacher use this to enhance understanding?
Some thoughtsThe meaning of simultaneous equations.The meaning of a plotted graph.
Next exampleFind the point(s) of intersections of the
graphs and This example is different from the previous
one becauseThe domain is not givenIt is not a convenient example where the
answer(s) are “in your face”.So we choose our own domain and start
with
x f(x) g(x)
-5 36 6.25
-4 24 5.25
-3 14 4.25
-2 6 3.25
-1 0 2.25
0 -4 1.25
1 -6 0.25
2 -6 -0.75
3 -4 -1.75
4 0 -2.75
5 6 -3.75
f(-2) > g(-2)f(-1) < g(-1)
f(3) < g(3)f(4) > g(4)
Hence somewhere between x = -2 and x = -1 we will have f(x) = g(x). (We will look at the other value later on).
We keep the table as is, but change our domain to
We also change the steps and make that 0,25.
x f(x) g(x)
-2 6 3.25
-1.75 4.3125 3
-1.5 2.75 2.75
-1.25 1.3125 2.5
-1 0 2.25
Also somewhere between x = 3 and x = 4 we will have f(x) = g(x).
We keep the table as is, but change our domain to
We also change the steps and make that 0,25.
x f(x) g(x)
3 -4 -1.75
3.25 -3.1875 -2
3.5 -2.25 -2.25
3.75 -1.1875 -2.5
4 0 -2.75
The graphs and intersect at(-1,5; 2,75)(3,5; 2,25)
Turning point of a parabolaFind the turning point of We do not know the range so we will start
with We do not need the second function, so we
CAN disable the second function.
x f(x)
-5 44
-4 31
-3 20
-2 11
-1 4
0 -1
1 -4
2 -5
3 -4
4 -1
5 4
So how can I use this as a teacher to enhance understanding?
Some thoughtsThe meaning of symmetryThe minimum valueThe meaning of a plotted graphThe shape of a quadratic function
Just checking – the turning point is (2; -5)
New exampleFind the turning point of We do not have a domain so we start with .
x f(x)
-5 118
-4 78
-3 46
-2 22
-1 6
0 -2
1 -2
2 6
3 22
4 46
5 78
The turning point should be
somewhere between x = 0
and x = 1
So……..We keep the table and change the domain
to….
And we make the steps…..
x f(x)
0 -2
0.25 -2.75
0.5 -3
0.75 -2.75
1 -2
The turning point is
Next exampleFind the turning point of .We do not know the domain hence…
x f(x)
-5 96.5
-4 70
-3 47.5
-2 29
-1 14.5
0 4
1 -2.5
2 -5
3 -3.5
4 2
5 11.5
The turning point should be
somewhere between x = 1
and x = 3
We will change the domain to .The steps should be .
x f(x)
1 -2.5
1.25 -3.5
1.5 -4.25
1.75 -4.75
2 -5
2.25 -5
2.5 -4.75
2.75 -4.25
3 -3.5
The turning point should be
somewhere between x = 2 and x = 2.25
We will change the domain to .The steps should be .
x f(x)
2 -5
2.0625 -5.0234375
2.125 -5.03125
2.1875 -5.0234375
2.25 -5
The turning point is
Finding the intercepts with the axesFind the intercepts with both the axes of
the graph of .Domain .Steps of 1
x f(x)
-5 56
-4 42
-3 30
-2 20
-1 12
0 6
1 2
2 0
3 0
4 2
5 6
y intercept
x intercept
x intercept
Just checking……. Where will the
turning point be?
So how can I as a teacher use this to enhance understanding?
Some thoughtsThe meaning of vs the meaning of .The meaning of a plotted graphSolving of quadratic equation
Next exampleFind the intercepts with both the axes of .Domain .Steps of 1.
x f(x)
-5 -43
-4 -31
-3 -21
-2 -13
-1 -7
0 -3
1 -1
2 -1
3 -3
4 -7
5 -13
y-intercept
Turning point should be
here
No x-intercept?
Seems as there are no x-intercepts.
Focus on turning point first.
Will be between x=1 and x=2.
The turning point is below the x-axis.
All the graph values are below the x-axis.
So no x-intercepts.
x
1 -1
1.25 -0.8125
1.5 -0.75
1.75 -0.8125
2 -1
Next exampleFind the intercepts with both the axes of .Domain .Steps of 1.
x f(x)
-5 -119
-4 -75
-3 -39
-2 -11
-1 9
0 21
1 25
2 21
3 9
4 -11
5 -38
y-interceptTurning point should be
here
x-intercept should be
here
x-intercept should be
here
Somewhere between x = -2 and x = -1 the one x-intercept should lie and somewhere between x = 3 and x = 4 the other x-intercept should lie.
So we are going to look at smaller domains and smaller steps.
x f(x)
-2 -11
-1.75 -5.25
-1.5 0
-1.25 4.75
-1 9
x-intercept
x f(x)
3 9
3.25 4.75
3.5 0
3.75 -5.25
4 -11
x-intercept
Looking at the reciprocal function
Work with domain
x f(x)
-5 1.333333
-4 1.2
-3 1
-2 0.6666666
-1 0
0 -2
1 ERROR
2 21
3 9
4 -11
5 --38
y-intercept
Asymptote
x-intercept
Finding equations of graphsWe now need to move to the STATS modeLet us have a look at the MenuIs everybody sure how to get into STATS
mode?
Example – linear functionWe are going to work with the linear
regression.Find the equation of the straight line
through (-1; -1) and (2; 5).Type in the two points in the table (data). Find the coefficients remembering that in
stats the linear equation is . The equation is .Or as we know it .
Example – Quadratic function with intercepts givenTyping error on page 10 (first bullet please
change to Quadratic and not linear).Enter the three points in the table (data).Find the coefficients remembering that in
stats the linear equation is . The equation is .Or as we know it .
Example – Quadratic function with any three points.
Enter the three points in the table (data).Find the coefficients remembering that in
stats the linear equation is . The equation is .Or as we know it .
Example – Exponential function* with any two points.
Enter the two points in the table (data).Find the coefficients remembering that in
stats the linear equation is . The equation is .*The CASIO fx-82ZA PLUS calculator can
only do the exponential graph of the form .
Example – Quadratic function with the turning point and another point.
We need to find ANOTHER point. From the turning point we know the axis of
symmetry is at x = -1The point symmetrical to (0;5) will be (-2; 5).Enter the three points.Find the coefficients remembering that in
stats the linear equation is . The equation is .Or as we know it .