grade 10 mathematical literacy / graad 10 wiskundige ... · 2 hoofstuk 1 / chapter 1 oefening 1 /...
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Grade 10 Mathematical literacy / Graad 10 Wiskundige Geletterdheid
Work that must have been done by 10 June (for the year):
Werk wat klaar gedoen moes gewees het teen 10 Junie (vir die jaar):
Chapter 1 / Hoofstuk 1: Exercise (Ex.) / Oefening (Ex) 1 – P. 15 Ex. 2 – P. 20+21 Ex. 3 – P. 23 Ex. 4 – P. 27 Ex. 5 – P. 31 Ex. 6 – P. 33 Ex. 7 – P. 38+39 Ex. 8 – P. 44
Chapter 2 / Hoofstuk 2: Ex. 1 – P. 51 Ex. 2 – P. 59-61 Ex. 3 – P. 64+65 Ex. 4 – P. 66 Ex. 5 – P. 70+71
Chapter 3 / Hoofstuk 3: Ex. 1 – P. 75 Ex. 2 – P.77 Ex. 3 – P79
Chapter 4 / Hoofstuk 4: Ex. 1 – P. 88 Ex. 2 – P. 90+91 Ex. 3 – P. 99+100
Chapter 5 / Hoofstuk 5: Ex. 1 – P. 105 Ex. 2 – P. 107 Ex. 3 – P. 108+109 Ex. 4 – P. 111 Ex. 5 – P. 113
Chapter 9 / Hoofstuk 9: Ex. 1 – P. 181 Ex. 2 – P. 183 Ex. 3 – P. 186 (skip nr.3) Ex. 4 – P. 189
Chapter 6 / Hoofstuk 6: Ex. 1 – P. 119 Ex. 2 – P. 121 Ex. 3 – P. 124+125 Ex. 4 – P. 131+132
Work for period from 11 June – 2 July:
Werk vir die tydperk van 11 Junie – 2 Julie:
Chapter 7 / Hoofstuk 7:
Ex. 1 – P. 139
Ex. 2 – P. 142+143
Ex. 3 – P. 146
Ex. 4 – P. 148
(Must be done by 16 June)
Chapter 8 / Hoofstuk 8:
Ex. 1 – P. 169
Ex. 2 – P. 171
Ex. 3 – P.175+176
(Must be done by 22 June)
Chapter 11 / Hoofstuk 11:
Ex. 1 – P. 213
Ex. 2 – P. 215
Ex. 3 – P. 220
(Must be done by 26 June)
Chapter 10 / Hoofstuk 10:
Ex. 1 – P. 194
Ex. 2 – P. 200+201
Ex. 3 – P. 204+205
(Must be done by 2 July)
1
GR 10 Handboekoefeninge antwoorde:
Gr10 Text book exercises answers:
INDEX:
Chapter 1 / Hoofstuk 1 - P. 2 - 12
Chapter 2 / Hoofstuk 2 - P. 13 - 21
Chapter 3 / Hoofstuk 3 - P. 22 - 24
Chapter 4 / Hoofstuk 4 - P. 25 - 27
Chapter 5 / Hoofstuk 5 - P. 28 - 32
Chapter 6 / Hoofstuk 6 - P. 33 - 37
Chapter 7 / Hoofstuk 7 - P. 38 - 42
Chapter 8 / Hoofstuk 8 - P. 43 - 45
Chapter 9 / Hoofstuk 9 - P. 46 - 49
Chapter 10 / Hoofstuk 10 - P. 50 - 53
Chapter 11 / Hoofstuk 11 - P. 54 - 58
Chapter 12/ Hoofstuk 12 - P. 59 -
2
Hoofstuk 1 / Chapter 1
Oefening 1 / Exercise 1 (p.15)
1.1) 71 507, Een en sewentig duisend vyf honderd en sewe
Seventy one thousand five hundred and seven
1.2) 780 027, Sewe honderd en tagtig duisend en sewe en twintig
Seven hundred and eighty thousand and twenty seven
1.3)62,952, Twee en sestig komma nege vyf twee
Sixty two comma nine five two
1.4)53 448 921, Drie en vyftig miljoen vier honderd agt en veertig duisend nege honderd
een en twintig
Fifty three million four hundred and fourty eight thousand nine hundred and twenty
one
2.1) 22 900
2.2) 8 630 000
2.3) 2 034 000 010
2.4) 15 175 000
2.5) 3 200 000 000
3.1) Ja, want min mense het R67 457 spaar.
Yes, because few people have R67 457 to spare.
3.2) Want dit maak die getal kleiner klink en dit lees maklikker en vinniger.
Because it make the amount sound smaller and it reads easier and faster.
4.1) 12 > -12
4.2) -7oC > -14oC
4.3) R2 000 > -R5 000
4.4) -800 < -794
5) Die woonstel is die 6de woonstel op die 12de vloer.
The apartment is the 6th apartment on the 12th floor.
3
Oefening 2 / Exercise 2 (p.20 – 21)
1.1) 16 + 23 + 44
= 83
1.2) 211 + 99 + 812
= 1 122
1.3) 3 x 9 x 1000
= 27 000
1.4) (13 + 29) x 1000
= 42 000
1.5) 12 x 82
= 820 + 164
= 984
1.6) 13 + 29 x 1000
= 29 013
1.7) 24 x 80 ÷ 10
= 192
1.8) (4 200 – 800 + 1 000) ÷ 100
= 4 400 ÷ 100
= 44
2.1) 10 (2.6) 3 400
2.2) 80 (2.7) 3 512,32
2.3) 256 (2.8) 3
2.4) 69 (2.9) 167
2.5) 32
4
3.1) R500
3.2) R320
4.1) 10 x R1,20
= R12
4.2) R75 ÷ 50
=R1,50
Oefening 3 / exercise 3 (p.23)
1.1) 0,5333…rep
1.2) 0,19561243…
1.3) 3,25
1.4) 0,48654275…
2) 2 ¼m = 2,25m
Dus/thus 2,31m is verder/further
3.1) 3/20 = 0,15
3.2) 5 ¼ = 5,25
3.3) 21/4 + 31/5
= 105/20 + 124/20
= 229/20
= 11,45
3.4) 3½ x 5¼ + 5⅛
= 7/2 x 21/4 + 41/8
= 147/8 + 41/8
= 188/8
= 23,5
5
3.5) 16/1 ÷ 3/5
= 16/1 x 5/3
= 80/3
= 26,666…rep
3.6) ½ ÷ ¼
= 1/2 x 4/1
= 4/2
= 2
4.1) 0,25 > 0,1875
4.2) 0,15 = 0,15
5.1) R25
5.2) R7,50
Oefening 4 / Exercise 4 (p.27)
1.1) 4,7
1.2) 4,8
1.3) 4,75
1.4) 13,13
1.5) 2 346
1.6) 2 300
1.7) 2 000
1.8) 2 400 000
2.1) R 13,95
2.2) R 2,70
2.3) R 12,45
6
3.1) Amper 3 000 OF meer as 2 800
Almost 3 000 OR more than 2 800
3.2) meer as 120 000
More than 120 000
3.3) amper 5,5 miljoen
Almost 5,5 million
4.1) 37,1
4.2) 98,5
4.3) 89,7
5.1) 5 x 4
= 20 ÷ 6
= 3,3….rep
= 4 Houers/cartons
5.2) 328 ÷ 5
= 65,6
= 65 boksies/boxes
Oefening 5 / Exercise 5 (p.31)
1.1) 500ml x 3
= 1 500ml water
1.2) 800ml x 3
= 2 400ml water
1.3) 6liter x 3
= 18liter
7
2.1) 18 ÷ 9 = 2
45 ÷ 9 = 5
2 : 5
2.2) 174 ÷ 6 = 29
6 ÷ 6 = 1
29 : 1
2.3) 30 ÷ 10 = 3
5 liter = 5000ml
5000 ÷ 10 = 500
3 : 500
3.1) 15 x 4 = 60 blue/blou
3.2) 72 ÷ 4 = 18 white/wit
4.1) 25 : 1050
25 ÷ 25 = 1
1050 ÷ 25 = 42
T/O : L
1 : 42
4.2) 1 178 ÷ 38 = 31 teachers needed / onderwysers benodig
5.1) 4 + 5 = 9
342 ÷ 9 = 38
38 x 4 = 152
38 x 5 = 190
152 : 190
8
5.2) 1 + 2 + 3 = 6
342 ÷ 6 = 57
57 x 1 = 57
57 x 2 = 114
57 x 3 = 171
57 : 114 : 171
Oefening 6 / exercise 6 (p.33)
1.1) Want soos wat die oproep se lengte toeneem, sal die oproep se koste ook toeneem.
Because as the length of the call increases, so too will the cost of the call increase.
1.2.1) 48 x R 0,025
= R 1,20
1.2.2) 8min 22sec
= (8 x 60) + 22
= 480 + 22
= 502 sec x R 0,025
= R 12,55
2.1) R 250,00
2.2) Want hoe meer mense saam in die taxi ry, hoe minder sal elkeen betaal.
Because the more people use the taxi together, the less each one will have to pay.
Oefening 7 / Exercise 7 (p.38 – 39)
1.1) R 44,99/kg x 4,2kg
= R 188,96
1.2) R 53,99 ÷ R 44,99/kg
= 1,2kg
9
2) 8liter/100km = 12,5km/liter
2.1) 40liter x 12,5
= 500km
2.2) R150,00 ÷ R10,05
14,9liter → 15liter
15liter x 12,5
187,5 → 188km
2.3) 927 ÷ 12,5
= 74,16liter ÷ 40
=1,854 → 2 keer/times
2.4) 12,5km/liter
2.5) Km/liter, dit is makliker om berekeninge met hierdie formaat te doen.
Km/liter it is easier to do calculations with this format.
2.6) 600 ÷ 42 = 14,3
42 ÷ 42 = 1
14,3km/liter
EN/AND
600 ÷ 6 = 100
42 ÷ 6 = 7
7liter/100km
3.1) Bonus
3.2)Ace, omdat Bonus heel moontlik hul kaas in 1,8kg pakkies verkoop en jy dus baie kaas
gaan mors.
Ace, because Bonus is probably selling the cheese in 1,8kg packets, so you will waste
a lot of cheese.
4.1) 2500ml ÷ 100ml = 25
Dus/thus 80g x 25 = 2000g
10
4.2) 1500g ÷ 80g = 18,75
Dus/thus 100ml x 18,75 = 1875ml
5) T = A ÷ S
= 75 ÷ 105
= 0,714 x 60
= 42,8 → 43min
6) 200 ÷ 8 = 25sek
7) S = A ÷ T
= 375 ÷ 400
= 0,9375km/m x 60
= 56,25 → 56km/h
8) 4min 30sek = 270sek
270sek x 42
=11 340sek ÷ 60
=189min
= 3h 9min
Oefening 8 / Exercise 8 (p.44)
1.1) 310 ÷ 540
= 0,57 x 100
= 57%
1.2) 34 ÷ 91
= 0,37 x 100
= 37%
1.3) 0,086 x 100
= 8,6 → 9%
11
2.1) 67% > 17/27
2.2) 203/678 > 0,24
2.3) 35/48 < 16/20
3.1) 12 x 1,18
= 14,16
3.2) 137,5 x 0,055
= 7,56
137,5 – 7,56
= 129,94
4.1) 50 - 40
= 10
10 ÷ 40
= 0,25 x 100
= 25% verskil / difference
4.2) 9,5 – 8,2
= 1,3
1,3 ÷ 9,5
= 0,14 x 100
= 14% afname/decrease
5.1) 80 ÷ 0,95
= 84,21
5.2) 107,5 ÷ 1,25
= 86
6a) R 105 900 x 0,20
= R 21 180
12
b) R 133 500 x 0,209
= R 27 901,50
c) R 146 100 x 0,215
= R 31 411,50
13
Hoofstuk 2 / Chapter 2
Oefening 1 / Exercise 1 (p.51)
1.1) Elektrisiteits verbruik → Onafhanklik
Electricity usage → Independent
Bedrag betaal → Afhanklik
Ammount paid → Depandent
1.2) Geld ontrek → Onafhanklik
Money withdrawn → Independent
Ontrekkings koste → Afhanklik
Withdrawal cost → Dependent
2.1) Kontinue/continuos
2.2) diskreet / discrete
Oefening 2 / Exercise 2 (p.60 – 61)
1.1) 5 x R12,00
= R60,00
1.2)
Liter parafien 1 2 3 … 7 … 10
Koste (R) Cost (R)
12 24 36 … 84 … 120
1.3) Horisontaal / horizontal = Liter parafien
Vertikaal/ Vertical = Koste / Cost
14
1.4)
1.5.1) (6;R72)
1.5.2) (5;R60)
1.6) Want as die een vermeerder, vermeerder die ander met dieselfde faktor
Because as the one increases, the other increases by the same factor.
1.7) Diskreet, omdat die parafien in volle liters gekoop word.
Discreet, beacause the parafin is bought in full litres
1.8) Ja, omdat die grafiek ‘n reguit lyn is wat by die punt 0;0 begin.
Yes, because the graph is a straight line the starts at the point 0;0
2.1) Ja / Yes
2.2) Nee / No
0
20
40
60
80
100
120
140
0 1 2 3 4 5 6 7 8 9 10
Ko
ste
/ c
ost
Koste van parafien / cost of parfin
15
3.1)
Elektrisiteit wat verbruik is / Electricity used
0 10 20 … 50 … 200
Maandelikse koste (R) / Monthly cost (R)
R0 R7 R14 … R35 … R140
3.3) Koste = R0,70 x Eenhede gebruik
Cost = R0,70 x Units used
3.4) Want soos wat die een veranderlike vermeerde, vermeerder die ander met dieselfde
faktor.
Because as the one veriable increases, the other also increases by the same factor.
3.5) Ja, Omdat die grafiek ‘n reguit lyn is, wat by die oorsprong begin.
Yes, because the graph is a straight line that starts at the origin.
4.1) R120,00
4.2) R90,00
4.3) R15/maand
R15/month
4.4) Dalend / Decreasing
0
20
40
60
80
100
120
140
160
0 20 40 60 80 100 120 140 160 180 200
Co
st (
R)
Units used
Electricity usage and cost
16
4.5) Elke maand raak die geld minder
Every month there is less money left
4.6) Elke maand raak die geld met die selfde hoeveelheid minder
Every month the money decreases with the same amount
4.7) Daar is nie meer geld in die rekening oor nie.
There is no money left in the account.
Oefening 3 / exercise 3 (p.64 – 65)
1.1)
Aantal leerders op die uitstappie / Amount of learners on trip
1 2 3 … 10 … 25
Bedrag wat elke leerder sal moet betaal (R) / Amount each has to pay (R)
2000 1000 666,67 … 200 … 80
1.2)
1.3) Slegs punte, omdat die hoeveelheid leerders diskrete data is en daar nie breukdele van
leerders kan saamgaan nie
Only plotted marks, because the learners is discreet data and there will not be fractions
of learners going on the trip
0
500
1000
1500
2000
2500
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
Bus hire cost
17
1.4) Want soos wat die hoeveelheid leerders vermeerder, verminder die bedrag wat elkeen
moet betaal met dieselfde faktor.
Because as the learners that are going on the trip increases, the amount each has to
pay decreases by the same factor.
1.5) +/- R130,00
1.6) Bedrag wat elkeen betaal = R2000 ÷ Hoeveelheid leerders
Amount each has to pay = R2000 ÷ Amount of learners
1.7) R2000 ÷ 30
= R66,67 elk/each
1.8) R2000 ÷ R87
= 22,9 → 23 learders/learners
2.1) 6
2.2) R189 429
2.3) (6 x R189429) + (37 x R21569) + (648 x R468) + (1324 x R470) + (26770 x R22) + (20267 x
R19) + (101240 x R10)
= R1 136 574 + R798 053 + R303 264 + R622 280 + R588 940 + R385 073 + R1 012 400
=R4 846 584
2.4)
Aantal mense wat 5 getalle reg het / Amount of people that have 5 numbers correct
1 2 3 … 6 … 10
Bedrag wat elk wen (R) / Amount each wins (R)
1 136 574 568 287 378 858 … 189 429 … 113 657,40
2.5) Want, hoe meer wenners daar is, hoe mider wen elkeen.
Because the more winners there are, the less each will win.
2.6) Dit sal ‘n afnemende of negatiewe kurwe wees, wat loop vanaf die links bo, na die regs
onder.
It will be a declining or negative curve starting in the top left and going down to the
bottom right.
18
2.7) Bedrag wat elkeen wen = R 1 136 574 ÷ Hoeveelheid wenners
Amount each will win = R 1 136 574 ÷ Amount of winners
2.8) R 1 136 574 ÷ 12
= R 94 714,50
Oefening 4 / Exercise 4 (p.66)
1.1) R 3 500
1.2) R 3 500
2)
3.1) Omdat die prys om die bus te huur dieslfde bly ongeag hoeveel mense daarop ry.
Because the cost to hire the bus will stay the same for any amount of passengers.
3.2) Omdat die hoeveelheid leerders diskrete data is, daar sal nie breukdele van leerders op
die bus ry nie.
Because the amount of learners is discreet data, there can’t be fractions of learners
on the bus.
0
500
1000
1500
2000
2500
3000
3500
4000
0 5 10 15 20 30 35 40 45 50 55 60 65
P
r
i
c
e
Amount of passengers
Cost to hire a bus
19
Oefening 5 / Exercise 5 (p.70 – 71)
1.1) K = R1,50 x 22
= R33,00
1.2) R19,50 = R1,50 x L
L = R19,50 ÷ R1,50
L = 13min
1.3) K = R1,50 x 5,75
= R8,63
2.1) K = R100 + (R2 x 100)
= R100 + R200
= R300
2.2) R100
2.3) R2/min
2.4) Opsie 1 /Option 1
2.5.1) R340 = R100 + (R2 x min)
(R2 x min) = R340 – R100
R2 x min = R240
Min = R240 ÷ 2
Min = 120
2.5.2) Min = (R524 – R100)÷2
= R424 ÷2
= 212
3) Die grafiek sal ‘n toenemende reguit lyn wees wat by die punt (0minute;R100) begin.
The graph will be a straight line that will increase consistantly, but will start at the
point (0minutes ; R100).
20
4.1) Dit beskryf hoeveel van die totale koste van die kaartjie elke wedstryd opmaak.
It describes how much of the total cost of the ticket each match makes up.
4.2) RK = R580 ÷ 10
= R58 per wedstryd/match
4.3) R72,50 = R580 ÷ games
R72,50 x games = R580
Games = R580 ÷ R72,50
Games = 8
4.4) R580
4.5) Dit is omdat hoe meer wedstryde mense gaan kyk met ‘n seisoen kaartjie, hoe minder
raak die relatiewe koste per wedtryd.
It is because the more matches you go and watch with the season ticket, the lower
the relative cost per match will become.
4.6)
4.7) 4.2: (10games ; R58)
4.3: (8games ; R72,50)
0
100
200
300
400
500
600
700
1 2 3 4 5 6 7 8 9 10
Ko
ste
/co
st (
R)
Games
Relatiewe koste / Relative cost
21
4.8) Omdat dit nie saak maak hoeveel wedstryde jy in die seisoen gaan kyk nie, die koste per
wedsryd sal nooit R0 wees nie.
Because it does not matter how many matches you go and watch throughout the
season, the cost per match will never be R0
4.9) Stippellyn, omdat daar nie halwe wedstryde geskeduleer sal word nie.
Dotted line, because they will never schedule half a match.
22
Hoofstuk 3 / Chapter 3
Oefening 1 / Exercise 1 (p.75)
1.1) 12m x 100
= 1 200cm
1.2) 1,35kg x 1000
= 1 350g
1.3) 23,5ml ÷ 1000
= 0,0235liter (Eng answer) ÷ 1000
= 0,0000235kl (Afr antwoord)
1.4) 13500cm ÷ 100
= 135m ÷ 1000
= 0,135km
1.5) 84,3cm ÷ 100
= 0,843m
1.6) 356g ÷ 1000
= 0,356kg
2.1) 5 x 250
= 1250ml
2.2) (3 x 250) + (5 x 5)
= 750 + 25
= 775ml
2.3) 150 ÷ 15
= 10 eetlepels/tablespoons
2.4) 75 ÷ 5
= 15 teelepels / teaspoons
23
Oefening 2 / Exercise 2 (p.77)
1 Afrikaans:
In Woorde In vm./nm. –formaat In 24 uur-formaat
10-uur die oggend 10:00vm 10:00
Sewe uur in die oggend 7:00vm 07:00
Drie uur in die middag 3:00nm 15:00
Half-7 in die oggend 6:30vm 06:30
Kwart voor twaalf in die oggend 11:45vm 11:45
Vyf en twintig oor agt in die aand 8:25nm 20:25
1 English
In Words In am/pm format In 24 hour format
10 o’clock in the morning 10:00am 10:00
Seven o’clock in the morning 7:00am 07:00
Three o’clock in the afternoon 3:00pm 15:00
Half past six in the morning 6:30am 06:30
Quarter to twelve in the morning 11:45am 11:45
Twenty five past eight in the evening 8:25pm 20:25
2.1a) Twintig oor een in die oggend – 1:20vm
Twenty past one in die morning – 1:20am
b) Vyf voor vyf in die oggend – 4:55vm
Five to five in die morning – 4:55am
2.2a) Twintig oor een in die middag – 1:20nm
Twenty past one in the afternoon – 1:20pm
b) Vyf voor vyf in die middag – 4:55nm
Five to five in the afternoon – 4:55pm
Oefening 3 / Exercise 3 (p.79)
1.1) (6x 60) + 30
= 390min
24
1.2) 24 450 ÷ 60
=407min 30sec
407 ÷ 60
=6h47m30s
1.3) 345 ÷ 24
= 14d9h
1.4) 3 x 24
= 72h x 60
= 4 320min
1.5) 145 200 ÷ 60
=2 420 ÷ 24
= 100d 20h
1.6) 28 ÷ 7
= 4weeks
1.7) 45 ÷ 7
= 6weeks 3days
1.8) 28 x 7
= 196days
2.1) 8Jul – 10 Okt
= 13weeks 3days
2.2) 2Aug – 5Sept
= 4weeks 5days
2.3) 8Jun – 1 Okt
= 16weeks 3days
25
Hoofstuk 4 / Chapter 4
Oefening 1 / Exercise 1 (p.88)
1) 30/6/2010
2) R310,03
3) R162,42
4) Versekering, Gespesifiseerde staat, Clip, Telefoon, SMS, MMS
Insurance, Itemised billing, Clip, Phone, SMS, MMS
5) R3,51 + R20,17 + R7,45 + R51,75
= R82,88
6) Oproepe/calls + SMS + MMS
= R162,42 + R25,34 + R1,32
= R189,08
Oefening 2 / Exercise 2 (p.90 – 91)
1.1) 8/5/2011
1.2) Vier minute voor tien in die oggend
Four minutes to ten in the morning
1.3) R14,99
1.4) Want dit was heelmoontlik op uitverkooping.
Because it was probably on special.
1.5) R237.34
1.6) R240.00
1.7) R237.34 → R237.30
R240 – R237.30
= R2,70
26
1.8) 1 x R200 + 2 x R20
2 x R100 + 4 x R10
1.8.1) Aartappels / Potatoes
Brood / Bread
Rys / Rice
Suikermielies / Sweet corn
Kool / Cabage
1.8.2) R237,34 – R20,35
= R216,99
2.1) Laerskool Umthombo Primary
2.2) 6/5/2011
2.3) R155
2.4) R665
2.5) Januarie, Februarie, Maart en April
January, February, March and April
2.6) Want die skool stuur moontlik slegs kwartaalliks state uit.
The school probably only sends out statements every term
2.7) Debiet is die geld wat aan die skool geskuld word en krediet is die geld wat aan die
skool betaal is.
Debit is the money that is owed to the school and credit is the money that was paid
to the school.
Oefening 3 / Exercise 3 (p.99 – 100)
1.1) 100 x R0,70855
= R70,855 → R70,86
1.2) 413,9 x R0,70855
= R293,27
27
2.1) Omdat jy slegs hoef te betaal vir wat jy gebruik met hierdie stelsel.
Because you only need to pay for what you use with this system.
2.2) Omdat die koste met ‘n konstante koers styg.
Because the cost increases with a constant rate.
2.3) R500,00
2.4) 275kWh
2.5) 100 = R35,43
R35,43 x 9
= R318,87
3) R35,43 ÷ 100
= R0,3543/eenheid(unit)
So R300 ÷ R0,3543
= 846,7 eenhede(units)
28
Hoofstuk 5/ Chapter 5
Oefening 1/ Exercise 1 (p.105)
1.1) Boek/Book:
Lengte/Length = 40cm
Breedte/Breadth = 25cm
Deur/Door:
Lengte/Length = 2m
Breedte/Breadth = 1,2m
Klas/ class room:
Lengte / Length = 8m
Breedte / Breadth = 8m
1.2) Hoogte/Hight = 2m
Wydte/width = 1,2m
1.3) Lengte/Length = 8m
Breedte/Breadth = 8m
2.1) 28 skoenlengtes/shoe lenghts
2.2) 30cm
2.3) 28 x 30cm
= 840cm ÷ 100
= 8,4m
Oefening 2 / Exercise 2 (p.107)
1a) 45kg
b) 130g
c) 120g
29
Oefening 3 / Exercise 3 (p.108 – 109)
1.1) R34,99 ÷ 1000
= R0,03499 x 250
= R8,77/250g
1.2) R20,49 ÷ 25
= R0,8196 x 2
= R1,64/200g
1.3) 2,5kg, die pak is grooter en sal dan gewoonlik minder per gram uitwerk as ‘n kleiner pak
en omdat sy die suiker op ander plekke ook gebruik, sal daar nie maklik gemors word
nie.
2,5kg, the pack is bigger and will probably cost less per gram than a smaller pack and
because she also uses sugar in other things, there is a very small chance that any will go
to waste.
2.1) R9,99 x 6,75
= R67,43
2.2) R10,50 ÷ R10,99
= 0,955 kg (+/- 7 tamatie/tomatos)
3) R12,35 ÷ 250
= R0,0494/gram
EN
R 21,95 ÷ 450
= R0,0487/gram
So 450g is goedkooper/cheaper
30
4.1)
Afrikaans:
Aan
van
gsge
wig
Gew
ig n
a 1
maa
nd
Ver
and
erIn
g in
gew
ig
Gew
ig n
a 2
maa
nd
e
Ver
and
erin
g in
gew
ig
Gew
ig n
a 3
maa
nd
e
Ver
and
erin
g in
gew
ig
Gew
ig n
a 6
maa
nd
e
Ver
and
erin
g in
gew
ig
Tota
le v
eran
der
ing
in
gew
ig
Agnes 71,8 kg
70,9 kg
-0,9 kg
70,1 kg
-0,8 Kg
69,0 kg
-1,1 kg
65,8 kg
-3,2 Kg
-6Kg
Jane 68,3 kg
68,1 kg
-0,2 kg
68,4 kg
+0,3 Kg
68,2 kg
-0,2 kg
67,9 Kg
-0,3 Kg
-0,4kg
English:
Star
tin
g w
eigh
t
Wei
ght
afte
r 1
m
on
th
Ch
ange
in w
eigh
t
Wei
ght
afte
r 2
mo
nth
s
Ch
ange
in w
eigh
t
Wei
ght
afte
r 3
mo
nth
s
Ch
ange
in w
eigh
t
Wei
ght
afte
r 6
m
on
ths
Ch
ange
in w
eigh
t
Tota
le c
han
ge in
wei
ght
Agnes 71,8 Kg
70,9 Kg
-0,9 kg
70,1 Kg
-0,8 Kg
69,0 kg
-1,1 Kg
65,8 Kg
-3,2 Kg
-6Kg
Jane 68,3 Kg
68,1 Kg
-0,2 Kg
68,4 Kg
+0,3 Kg
68,2 kg
-0,2 kg
67,9 kg
-0,3 Kg
-0,4kg
4.2) Agnes omdat sy 6kg verloor het.
Agnes because she lost 6kg.
4.3) Ja, omdat jy kans staan om 6kg in 6maande te verloor.
Yes, beacause you have a chance to loose 6kg in 6 months
5.1) 500kg
5.2) 500kg ÷ 10kg
= 50sakkies/bags
31
5.3) 500kg – 340kg
= 160kg
5.4) 50 x 7kg
= 350kg
So 280kg + 350kg
= 630kg, wat die bakkie gaan oorlaai
Which will overlood the bakkie
5.5) Want dit oorwerk die remme,asook die sispensie en dit verhoog petrol verbruik.
Because it puts too much strain on the brakes aswell as the suspention and it
increases fuel consumption.
Oefening 4 / Exercise 4 (p.111)
1.1) Nee dit was nie, omdat 2 x 1,5liters goedkoper sou uitwerk.
No, because 2 x 1,5liters would have worked out cheaper.
1.2) Nee dit kos mider as dubbel, omdat om in grooter maat te koop oor die
algemeengoedkoper is en omdat die verpakking vir bv. 2 1liter bottels meer sal
wees as vir 1 2liter bottel
No it does not cost twice as much, because buying in bulk usualy works out
cheaper and the packaging for 2 1liter bottles for example will cost more than the
packaging for 1 2liter bottle.
2) Melk/milk: 200ml ÷ 250
= 0,8 koppies/cups
Sout/salt: 10ml ÷ 5
= 2 teelepels/tea spoons
Suutlemoensap/ lemon juice: 20ml ÷ 15
= 1,333… eetlepels/ table spoons
32
3) water: 2 x 250
= 500ml
Bakpoeier/ baking powder: 1,5 x 5
= 7,5ml
Olyfolie/ olive oil: 2 x 15
= 30ml
Oefening 5 / Exercise 5 (p.113)
1a) 71oF en/and 25oC
b) 94oF en/and 37oC
2.1) 30oC
2.2) Johannesburg
2.3) 20oC
2.4) Port Elizabeth
2.5) Somer, omdat Johannesburg slegs in die sommer sulke hoë temperature het.
Summer, because Johannesburg will only have such high tempertures in the
summer.
2.6) Ja, Port Elizabeth is bietjie koeler, so die persoon mag dalk ‘n trui will aantrek.
Yes, Port Elizabeth is a bit colder, so the person may want to wear a jersey.
3) Kaapstad/Cape town:
F= 1,8 x 25 + 32
F = 77o
Johannesburg:
F = 1,8 x 30 + 32
F = 86o
33
Hoofstuk 6 / Chapter 6
Oefening 1 / Exercise 1 (p.119)
1) Om mense te help by die regte lokaal uitkom en dit is vir iemand wat nog nie die gebou se
uitleg ken nie.
To help people to get to the right classroom and it is for someone who doesn’t
know the lay out of the building yet.
2) 4
3) Grondvloer, Die “G”voor die klaskamer nommer beteken dat dit op die grondvloer is.
Ground floor, Beacause the “G”in front of the class room number indicates that
it is on the ground floor.
4) 1ste vloer/ 1st level
5) Trappe / steps
6) Gr12
7) Daar is nie/ there aren’t any
8) 2
9) U23 en/and U24
10) G1
11) G2 of G3, want dit is naby aan die personeelkamer en die ingang.
G2 or G3, because it is close to the staff room and the entrance.
Oefening 2 / Exercise 2 (p.121)
1) U25
2.1) Op die grondvloer langs die binnehof
On the ground floor next to the court yard.
2.2) Langs klaskamer G2 en oorkant die personeelkamer.
Next to room G2 en oposite the staff room.
34
2.3) Tussen die wetenskaplab en die spaarkamer.
Between the science lab and the spare room.
2.4) Tussen die trappe en kamer U22
Between the steps and room U22
2.5) Tussen die trappe en kamer G9
Between the steps and room G9
2.6) Tussen kamer U 22 en die spaarkamer.
Between room U22 and the spare room.
Oefening 3 / Exercise 3 (p.124 – 125)
1.1) Gr 5
1.2) Gr4 – Gr12
1.3) 26/27
1.4) 4
1.5) Trappe/steps
1.6) Dat die lokaal op die grondvloer is
That the room is on the ground floor
1.7) Grondvloer, want hulle is op hul eie en daar is geen klasse onder hulle nie, so dus moet
hulle op die grondvloer wees
Ground floor, because they are on their own, with no classes below them, so they
have to be on the ground floor.
1.8) U2 en G10 kan omgeruil word sodat al die gr10 klasse by mekaar is, sowel as die gr12
klasse en G18 en 19 se gr7s kan omruil met G14 en 15 se gr8s, sodat al die gr7s en gr8s
naby mekaar is.
U2 and G10 could be switched around, so that all the gr10s and all the gr12s are
together, aswell as G18 and 19’s gr7s can switch with G14 and 15’s gr8’s so that all
the gr7s and gr8s are close to each other
35
1.9) Ja, dit is die groen blok lang die skool gebou.
Yes, it’s the green block next to the school building.
1.10) donker blou/dark blue – admin rooms
Oranje/orange – Gr5 en computer lab
Lig blou / light blue – gr7
Pers/purple – gr8
Geel / yellow – gr6 and gr9
Lig groen / light green – gr4 en gr 11
Violet and peach – gr10
Pink – gr12
1.11) 4/5: Stoor/store room
Personeelkamer/ staff room
Admin kantoor / Admin office
Hoof se kantoor/ pricipal’s office
Computer lab
1.12) Parkeerarea / Parking lot
1.13) Langs die sportveld
Next to the sports field
1.14) In die oop blok tussen al die klasse
In the open area between all the classes.
1.15) 26 x 40
= 1040
1.16.1) Rekenaarkamer / Computer lab
1.16.2) Badkamers / Bathrooms
36
1.17)Die Gr12 klasse is op die grond en eerste vloer aan die ver kant van die gebou, langs die
gr4 klasse
The gr12 classes are on the ground and 1st floor on the far side of the building, next
to the gr4 classes.
Oefening 4+6 / Exercise 4 (p.131 – 132)
1.1) 10cm x 100
= 1000cm ÷ 100
= 10m ÷ 1000
= 0,01km
1.2) 172mm x 50 000
= 8 600 000mm ÷ 1000
= 8 600m ÷ 1000
= 8,6km
2.1) 3,7cm
2.2) 3,7cm x 5000
= 18 500cm ÷ 100
= 185m ÷ 1000
= 0,185km
3) Lengte/Length = 1,8cm x 5000
= 9000cm ÷ 100
= 90m
Breedte/width = 1,3cm x 5000
= 6500cm ÷ 100
= 65m
4.1) 15cm = 15km
37
4.2) 33mm = 1000m
So 11mm = 333,33m
So 22mm = 666,66m
So 220mm = 6,667km
4.3) 1cm = 50m
So 18,2cm = 910m
5.1) 3,7cm + 1,3cm + 2,2cm + 1,5cm + 1cm + 0,7cm
= 10,4cm (1cm = 50m)
So 10,4cm = 520m
5.2) 4,5cm + 7cm + 5cm + 4,5cm + 2,3cm + 3,3cm + 0,5cm + 4,4cm + 5cm
= 36,5cm (1cm=50m)
So 36,5cm = 1825m = 1,825km
38
Hoofstuk 7 / Chapter 7
Oefening 1 / Exercise 1 (p.139)
1.1) 1/6 or 0,16667 or 16,67%
1.2) 3/6 = ½ or 0,5 or 50%
1.3) 2/6 = 1/3 or 0,3333 or 33,33%
2.1) 5/9 or 0,5556 or 55,56%
2.2) 3/9 = 1/3 or 0,3333 or 33,33%
2.3) 4/9 or 0,4444 or 44,44%
3.1) 1/10 or 0,1 or 10%
3.2) 2/10 = 1/5 or 0,2 or 20%
3.3) 3/10 or 0,3 or 30%
3.4) Nee, want die kans dat jy ‘n prys gaan wen wat jou geld werd is, is 20%
No, because the chance that you are going to win a prize that is worth the money
you spent is only 20%
Oefening 2 / Exercise 2 (p.142 – 143)
1.1) 23oC
1.2) 14oC
1.3) Moontlikheid van reen, meestal bewolk en matig.
Chance of rain, mostly cloudy, moderate
2) Klein kans vir reen
Small chance of rain
3) Ja ek sou
Yes I would
4) Omdat hulle weet dat dit mense deurmekaar sou maak
They know that it would confuse people
39
5) Omdat die reen op enige tyd dalk mag ophou
Because the rain can stop at any moment for any reason.
6) Omdat die mense in daai ouderdomsgroep geneig is om ‘n hoër risiko lewe te lei.
Because the people in that age group are more likely to lead higher risk lifestyles.
7) Die kanse dat ‘n roker kanker en hartsiekte kan kry is hoër, maar dis nie definitief nie.
The chance of getting cancer and heart disease is higher, but not definite.
8) Dat 10% van mense wat die produk gebruik wel swart tande kan ontwikkel, maar die kans
is eintlik skraal.
That 10% of the people who use the product may get black teeth, but the chance is
actually slim.
9.1) 82/315 or 0,26 or 26%
9.2) 315 – 82 = 233/315 or 0,74 or 74%
9.3) 420 x 0,26 = 109
10.1) 18/250 = 9/125 or 0,072 or 7,2%
10.2.1) Ja dit is
Yes it is
10.2.2) Omdat dit die waarskynlikheid klein laat klink.
Because it makes the probability seem smaller.
10.2.3) 7
10.2.4) Want dit is nie definitief nie
Because it is not definite.
40
Oefening 3 / Exercise 3 (p.146 – 147)
1)
Maniere om te wen Lekkers gewen Totale aantal lekkers
Meisies K + M 2 4
M + K 2
Seuns K + K 3 4
M + M 1
Ways to win Sweets won Total ammount of sweets
Girls H + T 2 4
T + H 2
Boys H + H 3 4
T + T 1
2.1) (2.2)
Test1
Positive
Test 2 Positive Uses drugs
Test 2 negative May be using drugs
Negative
Test 2 Positve May be using drugs
Test 2 negative Does not use drugs
3)
Coin
Heads
Dice
1
2
3
4
5
6
Tails
Dice
1
2
3
4
5
6
4.1) 1/2 x 1/6 = 1/12
41
4.2)1/2 x 1/6 = 1/12
4.3) 1/2 x 1/2 = 1/4
5) Nee want jou kanse om te wen is aansienlik kleiner as sy kanse
No beacause the chance of you winning is much smaller than his chances.
Oefening 4 / Exercise 4 (p.148 – 149)
1.1)
For against undecided Total
Men 212 87 25 324
Women 52 30 77 159
Total 264 117 102 483
1.2) “skip”
1.3.1) 212/324
=0,65 x 100
= 65%
1.3.2) 77/159
=0,48 x 100
= 48%
1.4) Ja, want daar is meer mense wat ten gunste is as wat daar mense is wat teen dit is of
selfs besluitloos is, saam.
Yes beacause there are more people who are for it than there are people who are
against it and undecided, put together.
2.1)
Under weight Average weight Over weight Total
Gr8 0 1 1 2
Gr9 1 2 1 4
Gr10 0 4 1 5
Gr11 2 1 4 7
Gr12 0 4 2 6
Total 3 12 9 24
42
2.2.1) 24
2.2.2) 9
2.2.3) 1
2.3.1) 0/2 = 0,00 = 0%
2.3.2) 4/6 = 2/3 = 0,6667 = 66,67%
2.4) Want hy/sy sal wil weet wat is die gesondheidstoestand van sy/haar leerders.
Because he/she would want to know what the health status of his/her learners is.
2.5) Die graad 11’s, omdat daar 2 onder gewig en 4 oorgewig is uit 7
The Grade 11s, because there are 2 that are under weight and 4 that are over weight
out of 7
43
Hoofstuk 8 / Chapter 8
Oefening 1 / Exercise 1 (p.169)
Discription Income/ expence
F, Ve or O H or L
Teacher’s salary Income F
Cellfone airtime Expence Ve L
Allowance Income O
Schoolfees Expence F H
Money earned by a street vendor, selling vegetables Income Ve
Cash gift from a family member Income O
Replacing of car tyres Expence O H
Buying a pair of shoes Expence O L
Groceries Expence Ve H
Policeman earning overtime Income O
Commision earned by a salesman Income Ve
Transport (taxi or bus) Expence Ve H
Monthly payment for a funeral policy Expence F H
2.1) Income – Expences
= R100 – (R25 + R20 + R10 + R30 + R10)
= R100 – R95
= R5 left over at the end of the month
2.2) Versnapering/Refreshments
Selfoon-lugtyd/cellphone airtime
Oefening 2 / Exercise 2 (p.171)
1) R500,00
2) R4810,00 + R6975,00
= R11 685,00
3) R2500 + R320 + R180 + R80 + R430 + R450 + R220 + R500 + R300 + R300 + R60
= R5340
44
4) Income – Expences
= R11 685 – R11 630
= R55 surplus
5) Dit sal beteken dat hulle ‘n R25 tekort gaan hê.
That would cause them to have a R25 shortage.
6)a) Hulle kan probeer elektrisiteit en water bespaar.
They can try to save on eletricity and water.
b) Hulle kan probeer minder tyd op hul fone spandeer.
They can try to spend less time on their phones.
c) Hulle kan probeer om minder klere per maand te koop.
They can try to buy less clothes every month.
d) Hulle kan minder aan vermaak spandeer.
They can spend less on entertainment.
Oefening 3 / Exercise 3 (p.175 – 176)
1.1) R980
1.2) R650
1.3) 25
1.4) R980 ÷ 25
R39,20 → R40
1.5) R15 x 20
= R300
So R50 + R50 + R300 + R100 + R30 + R250 + R300
= R1080
So R1080 ÷ 25
= R43,20 → R45
45
2.1) R220
2.2) R330
2.3) Omdat sy nie elke maand die selfde afstande hoef af te lê nie.
Because she does not need to travel the same distances every month
2.4) (R220 + R180 + R230) ÷ 3
= R630 ÷ 3
= R210 Dis haar gemiddelde selfoon uitgawe vir die laaste 3 maande/ is the average
that she spent on her cellphone for the last 3 months
2.5) R75, Die bankkoste in Oktober het gestyg, so sy kan aanvaar dat dit die waarde vir die
volgende maand ook sal wees/ Because the banking cost for October went up, so she
can assume that this will be the ammount for the next month aswell
2.6) Ja/Nee, “met goeie rede”
Yes/no, “with a good reason”
46
Hoofstuk 9 / Chapter 9
Oefening 1 / Exercise 1 (p.181)
1) 12,3m + 10,8m + 4,7m + 4,3m + 7,6m + 6,5m – 2m
= 44,2m
2.1) 2(70m + 20m + 100m + 20m)
= 2(210m)
= 420m
2.2) 5 x 420m
= 2100m → 2km
2.3) 12 000m ÷ 420m
= 28,6 → 29 keer/times
Oefening 2 / Exercise 2 (p.183)
1.1) 2 x 3,142 x 10mm
= 62,84mm
1.2) 2 x 3,142 x 11,5mm
= 72,27mm
1.3) 3,142 x 7,5mm + 15mm
= 38,57mm
2.1) Swembad/swimmingpool:
2(8m + 4m)
= 2(12m)
= 24m
Heining/fence: 2(10m + 6m) = 2(16m) = 32m
Koste/cost: R275 x 32m= R8 832
47
2.2) Swembad/swimming pool
2 x 3,142 x 3,5m
= 21,994m
Heining/fence
2 x 3,142 x 4,5m
= 28,278m
Koste / cost
R275 x 28,278m = R7 776,45
2.3) Swembad / swimming pool
(2 x 3,142 x 2m) + (2 x 7m)
= 12,568m + 14m
= 26,568m
Heining / Fence
(2 x 3,142 x 3m) + (2 x 7m)
= 18,852m + 14m
= 32,852m
Koste / cost
R275 x 32,852m
= R9 034,30
Oefening 3 / Exercise 3 (p.186)
1) 16cm x 9cm
= 144cm2
2) 12,5cm x 12,5cm
= 156,25cm2
48
3) “som werk nie uit nie”
“sum doesn’t have an answer”
4) (44m x 39m) + ( 26m x 20m)
= 1716m2 + 520m2
= 2236m2
5) 2(3m x 5m) + (3m x 3,5m)
= 2(15m2) + 10,5m2
= 30m2 + 10,5m2
= 40,5m2
Oefening 4 / Exercise 4 (p.189)
1.1) 3,142 x 9cm x 9cm
= 254,5cm2
1.2) 0,5 x 3,142 x 15cm x 15cm
= 353,5cm2
1.3) 0,75 x 3,142 x 9cm x 9cm
= 190,9cm2
1.4) 3,6cm x 5,8cm
= 20,9cm2
1.5) (0,5 x 33 x 33) + (2 x 3,142 x 32) + 2(29 x 64) + (97 x 102)
= 544,5mm2 + 201,088mm2 + 2(1856mm2) + 9894mm2
= 745,588mm2 + 3712mm2 + 9894mm2
= 14 351,6mm2
2.1)a) (10m x 6m) – (8m x 4m)
= 60m2 – 32m2
= 28m2
49
b) (3,142 x 4,5m x 4,5m) – (3,142 x 3,5m x 3,5m)
= 63,63m2 – 38,49m2
= 25,14m2
c) [(3,142 x 3 x 3) + (6 x 7)] – [(3,142 x 2 x 2) + (4 x 7)]
= (28,28 + 42) – (12,57 + 28)
= 70,28m2 – 40,57m2
= 29,71m2
2.2)a) R345 x 28m2
= R9 660
b) R345 x 25,14m2
= R8 673,30
c) R345 x 29,71m2
= R10 249,95
50
Hoofstuk 10 / Chapter 10
Oefening 1 / Exercise 1 (p.194)
1.1) 4
1.2) 2
1.3) 4 + 4 = 8
2) Ja, want die aanwysings wys presies wat waar gaan en is maklik verstaanbaar.
Yes, because the diagram shows exactly what goes where and is easy to understand.
3) 1: Plaas die sitplekkussing tussen die pootrame en maak die dele aanmekaar vas met die
4, 1” skroewe
2: Maak die ruglening aan die pootrame vas met die 4, 1,5”skroewe
3: Trek die rugkussing oor met sy bedekking
4: Plaas die swart doppies bo-oor al die skroewe se koppe, die stoel moet nou reg wees
om te gebruik.
1: Place the seat cussion between the leg frames and fasten them using the 4, 1”screws.
2: Fasten the back cussion to the frames using the 4, 1.5”screws.
3: Cover the back cussion with its cover.
4: Place the platic caps over the heads of all the screws, the chair should now be ready to
use.
51
Oefening 3a / Exercise 2 (p.200 – 201)
1.1) Kamer 1: Kombuis
Room 1: Kitchen
Kamer 2: Hoofslaapkamer
Room 2: Main bedroom
Kamer 3: Badkamer
Room 3: Bathroom
Kamer 4: 2de slaapkamer
Room 4: 2nd bedroom
Kamer 5: Sitkamer
Room 5: Living room / Lounge
1.2) 2, Een in die gang by die sitkamer en die ander in die kombuis
2, One in the hall way next to the lounge and the other is in the kitchen.
1.3) Die een in die gang, omdat jy nie gaste deur jou kombuis wil verwelkom nie
The one in the hall way, because you do not want to receive guests through your
kitchen.
1.4) 5
1.5) Nomkhosi slaap in die hoofslaapkemer en Snegugu in die 2de slaapkamer, want dit is
Nomkhosi se huis.
Nomkhosi sleeps in the main bedroom and Snegugu in the 2nd bed room, because it’s
Nomkhosi’s house.
1.6) Toilet
Wasbak/ basin
Bad / bath
52
1.7) Stoof / Stove
Wasbak / basin
Kas / cupboard
Yskas / fridge
1.8) 26mm = 2m
So 1mm = 0,077m
Lengte / Length:
83mm x 0,077
= 6,4m
Breedte / width
63mm x 0,077
= 4,9m
2.1) 45
2.2) Ja, 3
Yes, 3
2.3) Omdat daar meer as een leerder is wie se naam Josh is.
Because the is more than one learner who’s name is Josh.
2.4) Dit is heelmoontlik die leesarea
That is probably the reading area
2.5) Teen die muur, tussen die leesarea en die onderwyser se lessenaar.
Against the wall, between die reading area and the teacher’s desk.
2.6.1) Aan die regtekant van die klas langs die leesarea.
On the right hand side of the class, next to the reading area.
2.6.2) Sy sit by die bank wat die verste is van die venster af en die naaste is aan die
onderwyser se lessenaar.
She sits at the table that is the furthest from the window and the closest to the
teacher’s desk.
53
Oefening 3b / Exercise 3 (p.204 – 205)
1.1.1) 4
1.1.2) 5
1.2) 4 x 5
= 20
1.3)
1.4) 4
1.5) 20 x 4
= 80
2.1) Nee, dit moet dieselfde hoeveelheid vat.
No, it should take the same ammount of cans.
2.2) 3 x 6 x 4 =72
3) 5 x 6 x 3 = 90
So rangskikking 1 vat 90 blikkie
rangskikking 2 vat 80 blikkies en rangskikking 3 vat 72 blikkies, so rankskikking 1 is
die beste
So arrangement 1 will take 90 cans,
arrangement 2 will take 80 cans and arrangement 3 will take 72 cans, so arrangment
1 is the best one.
4) Ja dit is, want die blikkies gaan meer stabiel op hulle plat kante staan.
Yes it is, because the cans will be more stable standing on their flat sides
5.1) 80
5.2) 72
54
Hoofstuk 11 / Chapter 11
Oefening 1 / Exercise 1 (p.213)
1.1) Dit beteken krediet, wat geld is wat aan die klient verskuldig is
It means credit, which is money that is owed to the client
1.2) Dis is verskuldig aan die persoon wie se telefoon dit is.
It is owed to the person who’s telephone it is.
1.3) R317,54 + R92,15 – R28,07
= R381,62
1.4) R381,62 x 0,14
= R53,42
1.5) R381,62 + R53,42
= R435,04
2.1)a) R149 ÷ 1,14
= R130,70
b) R149 x 1,14
= R169,86
2.2)a) R5,49 ÷ 1,14
= R4,82
b) R5,49 x 1,14
= R6,26
Oefening 2 / Exercise 2 (p.215)
1.1.1) Rentekoers/interest rate: 2%
Rente / interest: R20
Oorspronklike bedrag/ initial amount: R1 000
55
1.1.2) Rentekoers/ interrest rate: 1,6%
Rente / interest: R8
Oorspronklike bedrag/ initial amount: R500
1.1.3) Rentekoers/ interest rate: 7,2%
Rente / interest: R708
Oorspronklike bedrag / initial amount: R10 250
1.2.1) R1 000 x 0,02
= R20 korrek/correct
1.2.2) R500 x 0,016
= R8 korrek/correct
1.2.3) R10 250 x 0,072
= R738 (so R708 is inkorrek/incorrect)
2.1) R500 x 0,05
= R25
2.2) R500 + R25
= R525
2.3) R525 x 0,05
= R26,25 + R525
= R 551,25
3.1) R5 000
3.2) 0,625%
3.3) R5 000 x 0,00625
= R31,25
3.4) R5 000 + R31,25
= R5 031,25
56
3.5) R5 031,25 x 0,00625
= R31,45
3.6) R5 062,70 + R31,64
= R5 094,34
3.7) R5 094,34 + R31,84
= R5 126,18
3.8) R5 126,18 x 0,00625
= R32,04 + R5 126,18
= R5 158,22
Oefening 3 / Exercise 3 (p.220)
1.1) Ry 4 / Row 4
1.2) Ry 11 / Row 11
2) R8,30
3) Nee, omdat dit meer as die minimum van R1000, wat nodig is om die maandelikse fooie
vry te spring
No, because it is more than the minimum of R1000 that is needed to avoid the
monthly charges
4.1) R4,15 + 1,25% van die bedrag wat onttrek is.
R4,15 + 1,25% of the amount that was withdrawn.
4.2) R4,15 + (R850 x 0,0125)
= R4,15 + R10,63
= R14,78
5.1) R4,15 + 0,8% van die waarde van die transaksie, tot ‘n maksimum fooi van R35,50
R4,15 + 0,8% of the value of the transaction, up to a maximum charge of R35,50
57
5.2) R4,15 + (R3 800 x 0,008)
= R4,15 + R30,40
= R34,55
6) R4,15 + (R500 x 0,0125) + R6,70
= R4,15 + R6,25 + R6,70
= R17,10
7.1) R1 000 = R19
R1 750 = R29
R2 475 = R35
7.2) Omdat die fooi teen ‘n konstante koers vermeerder.
Because the fee increases at a constant rate
7.3) omdat daar ‘n minimum fooi betaal moet word, al is die transaksie slegs R0,01
Because there is a minimum fee that must be paid even if the transactions is only
worth R0,01
7.4) Want dit is waar die maksimum fooi van toepassing is.
Because that is where the maximum fee is charged.
7.5) R2 200
7.6) F = R4,15 + (A x 0,013)
R35,50 = R4,15 + (A x 0,013)
A x 0,013 = R35,50 – R4,15
A = R31,35 ÷ 0,013
A = R2 411,54
58
8) Debietkaart-aankope / Debit card payment: R4,15
OTM-onttrekking by eie bank se OTM/ ATM withdrawal at own bank’s ATM:
R4,15 + (R500 x 0,0125)
= R4,15 + R6,25 = R10,40
Debietorder tengunste van ander maatskappy/ debit order to another company:
R4,15 + ( R437,28 x 0,013)
= R4,15 + R5,68
= R9,83
Aftrekorder tengunste van rekening by ander bank/ stop order to account a different
bank:
R4,15 + ( R2 800 x 0,008)
= R4,15 + R22,40
= R26,55
Minimum rekening saldo onder R1000/ Minimum account balance below R1000:
R14,50
So: R4,15 + R10,40 + R9,83 + R26,55 + R14,50
= R65,43
59
Hoofstuk 12 / Chapter 12
Oefening 1 / Exercise 1 (p.227)
1.1) Numeries/numericle – diskreet/discrete
1.2) Katogories/catagorical
2.1)a) Watter sport verkies jy om aan deel te neem?
a) What sport do you prefer to participate in?
b) Watter sport is die mees populêr onder seuns/dogters?
b) Which sport is the most populer under the boys/girls?
c) Hoeveel tyd word per week aan sport bestee?
c) How much time is spent on sport per week?
d) Watter sport sou jy graag wil hê moet die skool adissioneel aanbied?
d) What sport would you like the school to offer?
2.2) a) Het jy tans ‘n selfoon?
a) Do you have a cell phone at the moment?
b) Indien ja, watter maak selfoon het jy?
b) If yes, what type of phone do you have?
c) Hoeveel tyd spandeer jy op jou foon per dag?
c) How much time do you spend on your phone per day?
d) Is daar ‘n ander maak foon wat jy sou verkies om te besit?
d) Is there another tipe of phone that you would prefer?
60
2.3) a) Gebruik jy dwelms?
a) Do you use drugs?
b) Watter dwelms gebruik jy?
b) What kind of drugs do you use?
c) Hoeveel dwelms gebruik jy ‘n dag?
c) How much drugs do you use every day?
d) Hoeveel kos jou dwelms jou per week?
d) Hom much does your drugs cost you every week?
Oefening 2 / Exercise 2 (p.229)
1) Dit sal akkuraat wees, omdat die steekproef groot genoeg is en leerders van alle rasse en
geslagte insluit.
It should be acurate because the sample size is big enough and includes people from
all races and genders.
2) Nee, want die steekproef van hierdie skool kan nie die totale prent van die hele land se
leerders verteenwoordig nie.
No, because the sample from this school can not represent the whole picture of all
the learners in the country.
Oefening 3 / Exercise 3 (p.231)
1.1) Hul ouderdomme en hoe gereeld hulle eet.
Their ages and how often they eat.
1.2) So dat hulle die gesondheids toestand van hulle leerders ken
So that they can monitor the welness of the learners.
1.3) Hulle kan sien of daar leerders is wat op ‘n voedingskema moet gaan.
They can see if there are learners that need to be on a feeding scheme.
61
1.4) Wanneer laas het jy ‘n ordentelikke maaltyd gehad?
When last dit you have a decent meal?
2) a)Hoe oud is jy?
How old are you?
b) Wat is jou geslag?
What is your gender?
c) Drink jy alkohol?
Do you drink alcohol?
d) Hoe gereld drink jy alkohol?
How often do you drink alcohol?
e) Wanneer jy alkohol drink, hoeveel drink jy?
When you drink alcohol, how much do you drink?
62
Oefening 4 / Exercise 4 (p.233)
1)
Van/Surname Naam/Name Geslag/ Gender
Punt/ mark (/50)
%
Berten Florence V/F 35 70
Dladla Nhlalala M 30 60
Dlamini Vuyo M 29 58
Franz Gladys V/F 31 62
Gnodde John M 37 74
Hlatshwayo Gabaza V/F 33 66
Hlone Lerato V/F 33 66
Hobdon Joseph M 26 52
Jarvel Julia V/F 30 60
Johnson Sylvia V/F 26 52
Khoza Sello M 23 46
Khumalo Serato V/F 32 64
Khumalo Tshimangadzo M 35 70
Mazibuko Khethiwe V/F 28 56
Mazibuko Nhlamulo M 11 22
Mbongwa Keketso M 20 40
Mnikathi Lufuno V/F 26 52
Murray Linda V/F 34 68
Naidoo Risimati M 17 34
Ndlela Mukomu M 31 62
Niven George M 45 90
Njoko Malesela M 37 74
Ntumba Tsakani V/F 25 50
Nxumalo Khensani V/F 29 58
Pillay Rhandzu V/F 24 48
Qwabe Hlulani M 12 24
Sibiya Vukati V/F 28 56
Smith Joe M 29 58
Steward Martha V/F 35 70
Taylor Lillian V/F 27 54
Zulu Thandeka V/F 35 70